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We are relying heavily on the fact that the cross-entropy with a
wrong model. It is fairly easy to show that this is so
- Solution:
-
We are only interested in showing that this number is negative, not
in its absolute value, so
we can drop the irrelevant factor of
and then use the fairly well-known fact that

to substitute into 9.2. This gives
Figure 9.2:
Plot of x-1 and log(x)
![\begin{figure}
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/gnudict 40 dict def...
...akebox(0,0)[r]{-2}}
\put(420,151){\makebox(0,0)[r]{-3}}\end{picture}\end{figure}](img93.gif) |
Chris Brew
8/7/1998